Comments on: Check username availability and validation using ajax,php

By: Nandini

Nandini — Mon, 26 Sep 2011 13:41:00 +0000

hi! can u please explain this part to me

echo json_encode(array(‘code’ => -1,
‘result’ => ‘Invalid username, please try again.’
));

By: queries

queries — Fri, 02 Sep 2011 17:37:25 +0000

Please specify what exactly the statement should be if I use JS callback method. I am getting error due to eval method.

By: shgun

shgun — Mon, 18 Jul 2011 12:20:54 +0000

i m not able to understand the whole code. cn u just give me how it functions in a general way

By: jaimin

jaimin — Wed, 22 Jun 2011 13:39:37 +0000

hi sachin
i want check availability code for number.
in my application i want unique id two times so first field i gave auto increment but other field also i want unique and it is a unique number can you give me the code for this and php code and javascript code and html code pls help me i am totally fresher in this field

By: Mwathi

Mwathi — Wed, 25 May 2011 09:17:07 +0000

Change your database, you must have left it as (db) and not ($Database)

By: MWathi

MWathi — Wed, 25 May 2011 09:14:22 +0000

Thanks for this code, works well, but some parts need to be changed, for instance, switching: echo json_encode(array(‘code’ => 0, ‘result’ => “Sorry but username $user is already taken.” with: echo json_encode(array(‘code’ => 1,
‘result’ => “Success,username $user is still available.” and VICE VERSA.

By: Jagannath Gummaluri

Jagannath Gummaluri — Sat, 11 Dec 2010 01:48:18 +0000

Hello Sachin,

I am going to try the above code which you have given. But I need lot of help in making a dynamic driven website in PHP and need lot and lots of help from you…. I hope you will help me as I go ahead with my work.

Thanks and Regards,
Jagannath G

By: manju

manju — Mon, 06 Dec 2010 12:31:13 +0000

mysql_connect(“localhost”,”root”,”kspl1234″);
mysql_select_db(“users”);
$user = strip_tags(trim($_REQUEST['username']));
$sql= mysql_query(“SELECT * FROM users where username=’”.$user.”‘ ” );
$num= mysql_num_rows($sql);
$row= mysql_fetch_array($sql);
if($sql)
{
echo “Not available”;
}
else
{
echo “Available”;
}

By: manju

manju — Mon, 06 Dec 2010 12:30:23 +0000

Hi sachin, firstly thanks for your code its working without mysql,, and wen im try to do with mysql its not even trying to functionate… please help me out…..
here is my code..

By: Johnny

Johnny — Sun, 28 Nov 2010 22:43:19 +0000

I have no errors using this, but it keeps telling the username is available although its already registered.

$query = “Select * from USERS where username = ‘$user’ “;

This is correct, i have a username field and a table called USERS.

Also added these as you suggested:
$result = mysql_query($query);
$available = mysql_num_rows($result);

dunno whats wrong

By: pooja

pooja — Tue, 16 Nov 2010 08:05:52 +0000

hi… can u plz send me the code of vadition and events using ajax..plz send me as soon as possible b’coz i hve interve the day after tommorow…..
thanxs

By: Daniel

Daniel — Sat, 06 Nov 2010 12:50:34 +0000

I know that. But it seems so work now, after i cleared the browser cache.

One other thing tho… how can i change it so i don´t have to press the submit button all the time? (mouseclick would be much better.)

By: Sachin Khosla

Sachin Khosla — Sat, 06 Nov 2010 03:00:58 +0000

Daniel,

You need to check that your MySQL returns proper results and then accordingly populate the $available variable .. Since this message depends on simple if/else loop/

By: Daniel

Daniel — Fri, 05 Nov 2010 18:10:47 +0000

I really like this simple code, BUT i can´t get it to work as it should.
I´m trying to use the code with my database, (with existing users), but the script says “Sorry but username trwtwrtwrt is already taken.”.

I have tried many bogus usernames, and all seems to be “taken” regarding this script.

By: Jim

Jim — Sun, 03 Oct 2010 22:24:45 +0000

I get the same thing in IE. I copied the code from the demo page. Any ideas?